6x^2+4x-98=0

Solution for 6x^2+4x-98=0 equation:

6x^2+4x-98=0

a = 6; b = 4; c = -98;
Δ = b2-4ac
Δ = 42-4·6·(-98)
Δ = 2368
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{2368}=\sqrt{64*37}=\sqrt{64}*\sqrt{37}=8\sqrt{37}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(4)-8\sqrt{37}}{2*6}=\frac{-4-8\sqrt{37}}{12}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(4)+8\sqrt{37}}{2*6}=\frac{-4+8\sqrt{37}}{12}
$